limx-0In(1+x2)/sin(1+x2)
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高数极限,不定积分,定积分①limx→3(x2-4x+3/sin(x-3))②limx→∞(x+1/x-2)*x③∫x2*√1+x3dx④∫xe(-x)dx⑤∫d(2x+3)②是limx→∞(x+1/
x2-3x-1=0,求①x21/x2;②x2-1/x2x2-3x-1=0,求①x21/x2;②x2-1/x2x2-3x-1=0,求①x21/x2;②x2-1/x2∵x2-3x-1=0∴X-2-1/X=
x2.sinα-y2.cosα=1(0x2.sinα-y2.cosα=1(0x2.sinα-y2.cosα=1(0x2sinα+y2cosα=1,即x2/(1/sinα)+y2/(1/cosα)=1,
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y=sin√1-x2y=sin√1-x2y=sin√1-x2y''=cos√(1-x^2)*(-2x)*(1/2)/√(1-x^2)=-x/√(1-x^2)*cos√(1-x^2)
limx→-∞x/√1+x2=limx→-∞1/-√1+1/x2这个是怎么化简过来的求解释limx→-∞x/√1+x2=limx→-∞1/-√1+1/x2这个是怎么化简过来的求解释limx→-∞x/√
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x2-3x+1=0x2/(x4-x2+1)x2-3x+1=0x2/(x4-x2+1)x2-3x+1=0x2/(x4-x2+1)请问这是什么啊?希望能把问题完善了好吧?
x2-5x+1=0则x2+x2/1x2-5x+1=0则x2+x2/1x2-5x+1=0则x2+x2/1你可以参见“韦达定理”方程两个根的积是1,说明他们互为倒数.x^2+1/x^2=(x+1/x)^2
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limx趋近于0x2/sin2(x/3)limx趋近于0x2/sin2(x/3)limx趋近于0x2/sin2(x/3)lim(x->0)x^2/(sin(x/3))^2(0/0)=lim(x->0)
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如何用求Matlab求方程组?假设有矩阵A=[sin(x1)+cos(x2),1;cos(x2),0],B=[sin(x2+x1)+cos(x1),1;sin(x2),0]现令A和B相等,怎么求出X1