记等差数列an的前n项和为Sn,若S2n-1=(2n-1)(2n+1),则Sn=?怎么解

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/27 22:03:17
记等差数列an的前n项和为Sn,若S2n-1=(2n-1)(2n+1),则Sn=?怎么解记等差数列an的前n项和为Sn,若S2n-1=(2n-1)(2n+1),则Sn=?怎么解记等差数列an的前n项和

记等差数列an的前n项和为Sn,若S2n-1=(2n-1)(2n+1),则Sn=?怎么解
记等差数列an的前n项和为Sn,若S2n-1=(2n-1)(2n+1),则Sn=?怎么解

记等差数列an的前n项和为Sn,若S2n-1=(2n-1)(2n+1),则Sn=?怎么解
另k=2n-1 然后n就等于 (k+1)/2 把 (k+1)/2带入n 求出来