已知奇函数f(x)是定义在(-3,3)上的减函数,且满足不等式f(x-3)+f(x2-3)

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/25 21:02:34
已知奇函数f(x)是定义在(-3,3)上的减函数,且满足不等式f(x-3)+f(x2-3)已知奇函数f(x)是定义在(-3,3)上的减函数,且满足不等式f(x-3)+f(x2-3)已知奇函数f(x)是

已知奇函数f(x)是定义在(-3,3)上的减函数,且满足不等式f(x-3)+f(x2-3)
已知奇函数f(x)是定义在(-3,3)上的减函数,且满足不等式f(x-3)+f(x2-3)

已知奇函数f(x)是定义在(-3,3)上的减函数,且满足不等式f(x-3)+f(x2-3)
既然是(-3,3)上的函数,那么x-3及x2-3不在定义域内,f(x-3)+f(x2-3)无意义,题目肯定是不对的,楼主应该确定题目正确

根据题意,可得-3<x-3<3-3<x2-3<3​,
解可得0<x<6-
6<x<
6​且x≠0,
故0<x<6,
又∵f(x)是奇函数,
∴f(x-3)<-f(x2-3)=f(3-x2),
又f(x)在(-3,3)上是减函数,
∴x-3>3-x2,即x2+x-6>0,
解得x>2或x<-3,综上得2<...

全部展开

根据题意,可得-3<x-3<3-3<x2-3<3​,
解可得0<x<6-
6<x<
6​且x≠0,
故0<x<6,
又∵f(x)是奇函数,
∴f(x-3)<-f(x2-3)=f(3-x2),
又f(x)在(-3,3)上是减函数,
∴x-3>3-x2,即x2+x-6>0,
解得x>2或x<-3,综上得2<x<6,即A={x|2<x<6},
∴B=A∪{x|1≤x≤5}={x|1≤x<6},
又g(x)=-3x2+3x-4=-3(x-12)2-知:g(x)在B上为减函数,
∴g(x)max=g(1)=-4.

收起

=9

Street shot shows the trend of wearing off-take
Each fall, the International Fashion Week held in total make the city become a trend-type people gathered to. The total gathered from various quar...

全部展开

Street shot shows the trend of wearing off-take
Each fall, the International Fashion Week held in total make the city become a trend-type people gathered to. The total gathered from various quarters trendsetters. Here,Air Jordan XX, take your Watch London Fashion Week this month show the trend of off-look! Present the hottest style, leather costume + pencil dress pants are scripted,Jordan 8 Retro, but also present the hottest style,jordan 10 shoes, leather costume + pencil pants. Topics related articles:


Jordan VII Retro Autumn and winter trends Puff Sleeve with _

Air Jordan 15 Decorate the warm autumn and winter

Jordan 7 Retro IN 08 big trends to watch _16

Swarovski Winter temptation _36 08

Nike Air Jordan 1 Heavy metals precious stone jewe

Jordan IV IN workplace after the leave, most dress

Jordan VI Mix and match up people with the Nordic

Air Jordan IV Long travel section T shirt fashion

Jordan 11 Jeans must comply with the eight laws of

Air Jordan XI Retro Comments Who installed the mos

Tube Top Small dress charm _38 T-Taiwan

Nike jordans Create the perfect dream wedding _134

Jordan VIII 11 travel light most eye-catching inst

Jordan XIII 12 early autumn shirt _103 aesthetic t

Buy Jordans A sweet handsome _74 sa Autumn Mashup

收起

已知f(x)是定义在(-3,3)上的奇函数,当0 已知定义在R上的奇函数f(x+3)=-f(x), 已知定义在R上的函数f(x)是奇函数且满足f(3/2-x)=f(x),求F(X)的周期 已知定义在R上的奇函数f(x),当x>0是f(x)=3x-1,求f(x)解析式 已知f(x)是定义在R上的奇函数,且当x>0时,f(x)=2的x次方-3,则f(-2)等于 已知函数f(x)是定义在R上的以3为周期的奇函数,且当0 已知y=f(x)是定义在[-5,2a-3]上的奇函数,则a的值为 已知周期函数f(x)是定义在R上的奇函数,周期为2,f(1)+f(2)+f(3)+…+f(2011)=? 已知y=f(x)是定义在R上的奇函数,当x小等于0时,f(x)=x^3-3x,则x 已知函数f(x)是定义上[-6,6]上的奇函数,且f(x)在[0,3]上是一次函数,在[3,6]上是二次函数,又当x∈[3已知函数f(x)是定义上[-6,6]上的奇函数,且f(x)在[0,3]上是一次函数,在[3,6]上是二次函数,又 已知f(x)是定义在R上的奇函数,且当x>0时,f(x)=3x平方+2x-1,则x 已知定义在R上的函数y=f(x)是奇函数,且x应该是x》0时,f(x)=x²-2x+3, 已知y=f(x)是定义在R上的奇函数,当x>0时,f(x)=x^2-2x-3,则x 已知f(x)是定义在(-1,1)上的奇函数.且在(-1,1)上为减函数,若满足f(1-a)+f(3a-2) 已知函数f(x)是定义在【-4,4】上的奇函数,且在[-4,4]上单调递减,若f(a+1)+f(a-3) 已知函数f(x)是定义在[-4,4]上的奇函数,且在[-4,4]上单调递增.若f(a+1)+f(a-3) 已知奇函数f(x)是定义在(-3,3)上的减函数,且满足不等式f(x-3)+f(x^2-3) 已知奇函数f(x)是定义在(-3,3)上的减函数,且满足不等式f(x-3)+f(x^2-3)