两道SAT2数学题1. A hotel has five single rooms available, for which six men and three women apply.What is the probability that the rooms will be rented to three men and two women?2.Of all the articles in a box, 80% are satisfactory, while 20% ar
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两道SAT2数学题1. A hotel has five single rooms available, for which six men and three women apply.What is the probability that the rooms will be rented to three men and two women?2.Of all the articles in a box, 80% are satisfactory, while 20% ar
两道SAT2数学题
1. A hotel has five single rooms available, for which six men and three women apply.What is the probability that the rooms will be rented to three men and two women?
2.Of all the articles in a box, 80% are satisfactory, while 20% are not. The probability of obtaining exactly five good items out of eight randomly selected articles is?
请附上详细过程及讲解.
另外,第二题答案上是这样说的.
Since the problem doesn't say how many articles are in the box, we must assume that it is an unlimited number. The probability of picking 5 satisfactory items(and therefor 3 unsatisfactory ones) is (0.8)5(0.2)3,这里5和3是次方.and there are(85){前面小括号里85是竖排的,上面是8,下面是5,请问这里什么意思}ways of doing this.Therefore, the desired probability is(85)(0.8)5(0.2)3约等于 0.147 .最后这个式子是怎么回事?
两道SAT2数学题1. A hotel has five single rooms available, for which six men and three women apply.What is the probability that the rooms will be rented to three men and two women?2.Of all the articles in a box, 80% are satisfactory, while 20% ar
第一题:
男女分五个房间的总数可能性是:P=C62*C33+C63*C32+C64*C31+C65*C30(这个文本框编辑要求达不到 所以学数学你应该也懂吧 前面的数字是下面 后面的数字是上面)
概率:C63*C32/P
第二题:
因为一盒东西放在那里,不知道总数,所以说明其中每个物品合格的概率是80%=0.8 不合格的概率是20%=0.2 那么从中挑出八个物品正好是五个好的三个坏的.但是在你挑的时候,哪出的物品顺序是不同的,所以用插空法可得出总共的顺序次数为A=C61+C31*C62+C63 这些物品哪出的概率为B=(0.8)5(0.2)3 所以最后的概率
P=A*B