limn趋向于无穷 （n+3/n+1）^n/2=?

limn趋向于无穷 （n+3/n+1）^n/2=? 请教用洛必达法则求极限问题：n趋向于正无穷,limn^3{a^（1/n）-a^(sin1/n)},a>0 感激~ 利用极限存在准则证明：limn趋向于无穷,n【1/（n^2+π）+1/（n^2+2π）+...+1/（n^2+nπ)】=1 limn趋向于无穷根号n3+3^n的极限怎么求 利用夹逼准则计算limn趋向于无穷(a^n+b^n)^1/n(a>0,b>0) n趋向于无穷 数列极限定义证明limn^(2/3)sinn/(n+1)=0,n趋向于无穷大,马上求解 lim根号n*n+n除以n+1=?（档n趋向于无穷） lim n趋向于无穷 n[(（n+1）/n)^n-e] limn趋向无穷大(2^(n+1)-3^n)/(3^(n+1)+2^n)=? 求limn→无穷(1+2^n+3^n+4^n+5^n)^1/n lim x趋向于无穷 (2^n+1+3^n+1)/(2^n+3^n)= 求lim趋向于无穷3^n+(-2)^n/3^(n+1)+(-2)^(n+1) (1+2^n+3^n)^(1/n) 其中n趋向于正无穷 求极限 n趋向于无穷 lim（(根号下n^2+1)/(n+1)）^n 求极限lim(n趋向于无穷）(n+1)(根号下(n^2+1)-n) limn^2(1-cosπ/n),n趋向无穷大 极限limn→无穷 (2n^2-3n+1)/n+1 sin1/n