1+1x2+2×3+3

解方程：X2--1/8(X2+2X)+X2+2X/3(X2--1)=11 已知x2－4x+1=0,求x2／(x2)2－3x2+1 2^5+5x2^4+10x2^3+10x2^2+5x2+1 x2-3x-1=0,求①x2 1/x2;②x2-1/x2 y=3x/1+x2的值域1-X2/1+X2→2-(X2+1)/1+X2→-1 + 2/(1+X2)这一步怎么得到的, 计算:x2-5x+6/x2-4x+3 + x2-4x+3/x2-2x+1 + x2-3x-4/1-x2 若 x2-3x+1=0,求（2x2×x3-5x2×x2+2 x3-8x2 ）÷（x2+1 ）的值 x2-3x+1=0 x2/(x4-x2+1) (1/2)^3x2^3与(1/2x2)^3 2x2+1+2+3+2x2= 证明：x2+3/根号x2+1≥2根号2 （x2+1/x2-2）3展开式常数项是? 6x2-[-3x2-(x-1)] 化简 约分 1-x2/x2-3x-4 化简1/x2-3x+2 +1/x2-x +1/x2+x +1/x2+3x+2 求和Sn=1x2+3x2^2+5x2^3+…+（2n-1）x2^n x2-3x+1=0,求x2+1/x2-2的值x2表示x的平方 用杨辉三角规律计算下题 2^5-5x2^4+10x2^3-10x2^2+5x2-1