① ﹙2y+1﹚2-8﹙2y+1﹚+15=0②x2-2√2x+2=0③2y2-2√2y-3=0④2x2-6x+1=0⑤3x2+8x-1=0
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①﹙2y+1﹚2-8﹙2y+1﹚+15=0②x2-2√2x+2=0③2y2-2√2y-3=0④2x2-6x+1=0⑤3x2+8x-1=0①﹙2y+1﹚2-8﹙2y+1﹚+15=0②x2-2√2x+2=
① ﹙2y+1﹚2-8﹙2y+1﹚+15=0②x2-2√2x+2=0③2y2-2√2y-3=0④2x2-6x+1=0⑤3x2+8x-1=0
① ﹙2y+1﹚2-8﹙2y+1﹚+15=0②x2-2√2x+2=0③2y2-2√2y-3=0④2x2-6x+1=0⑤3x2+8x-1=0
① ﹙2y+1﹚2-8﹙2y+1﹚+15=0②x2-2√2x+2=0③2y2-2√2y-3=0④2x2-6x+1=0⑤3x2+8x-1=0
4y+2-16y-8+15=0 所以-12y+9=0 所以y=3/4
X‘’-2√2x+(√2)"=0 所以(x-√2)''=0 所以x=√2
化为 (√2)''x''-2√2y-3=0 变为(√2y+1)(√2y-3)=0 所以 y=-√2/2 y=3√2/2
没时间了,
﹙2y-1/y﹚的8次的展开式中不含y的项是
y (3y^2+8y-3)-6y(3y+2y-1)+9y
分式的运算﹙x/x-y﹣2y/x-y﹚÷﹙x-2y/xy﹚×﹙1/x﹣1/y﹚
(y-2)(y^2-6y-9)-y(y^2-2y-15),其中y=1/2.先化简再求值.
若﹙2x+y-1﹚²+|x-2y-3|=0,求代数式﹙2x+y﹚﹙2x-y﹚-﹙x+2y﹚﹙x-2y-1)的值
[T,Y]=ode45(@rigid,[0 1],[rand(15,1)]);plot(T,Y(:,1),'-',T,Y(:,2),'-.',T,Y(:,3),'.',T,Y(:,4),'-',T,Y(:,5),'-.',T,Y(:,6),'.',T,Y(:,7),'-',T,Y(:,8),'-.',T,Y(:,9),'.',T,Y(:,10),'-',T,Y(:,11),'-.',T,Y(:,12),'-.',T,Y(:,13),'.',T,Y(:,14),'-',T,Y(:,15),'.')
已知实数x,y满足根号2x-3y-1+|x-2y+2|.求﹙5/2﹚x-﹙4/5﹚y的平方根
﹙-3y的n+1次方 + 4y的n+2次方 - 12y的n次方﹚÷﹙-24y的n-1方﹚
(y平方+2y)(y平方+2y+2)+1
方程y''=(1+y'*y')/2y的通解
y- 2y+1/2=9- 8-y/4
y-2y+1/2=9-8-y/4
y-2[y-4(y-1)]-8=0
y'=1+y^2
-1+y+20y^2
通分 y+3/y*y-6y+9,1/2y+6,y-1/y*y-9
[(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值