若x^2+y^2-10x-2y+26=0求根号x/4+根号y/2注:1.x/4在根号内,y/2也是 2.速度! 3.拜托~
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/16 01:28:21
若x^2+y^2-10x-2y+26=0求根号x/4+根号y/2注:1.x/4在根号内,y/2也是2.速度!3.拜托~若x^2+y^2-10x-2y+26=0求根号x/4+根号y/2注:1.x/4在根
若x^2+y^2-10x-2y+26=0求根号x/4+根号y/2注:1.x/4在根号内,y/2也是 2.速度! 3.拜托~
若x^2+y^2-10x-2y+26=0求根号x/4+根号y/2
注:1.x/4在根号内,y/2也是
2.速度!
3.拜托~
若x^2+y^2-10x-2y+26=0求根号x/4+根号y/2注:1.x/4在根号内,y/2也是 2.速度! 3.拜托~
x=5,y=1,答案即(根号5+根号2)除以2
x=5,y=1
答案=(根号5+根号2)/2
把原方程配成,两个完全平方式,即(x+2)^2+(x+5)^2=0
根据非负数相加得零,X=1,Y=5,代入求解
把已知的式子分解,变成 x^2-10x+25+y^2-2y+1=0 则原式即成为两个完全平方式 (x-5)^2+(y-1)^2=0 两个完全平方式相加等于0 则 x-5=+1-1 y-1=+1-1 则有四种情况 x=6,y=2或x=6,y=0或x=4,y=2或x=4,y=0,把这四个代入要求的式子就求出来了
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
若x-y不等于0,2x-3y=0,则分式(10x-11y)/(x-y)的值是()?(10x-11y)/(x-y) =[(8x-8y)+(2x-3y)]/(x-y) =8为什么8X-8Y=8?(10x-11y)/(x-y)=[(8x-8y)+(2x-3y)]/(x-y)=8+(2x-3y)]/(x-y)=8+0=8
若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*y)的值
若x^2+y^2-10x-6y+34=0,求(x-y)/(x+y)的值
若x^2+2x+y^2-6y+10=0,则x-y
若x^2+y^2-10x+6y+34=0,则x+y=?
若x²+2x+y²-6y+10=0求x y
若x.y满足条件2x+y-12=0,x-4y+10
若x^2-4x+y^2-10y+29=0,求x^2y^2+2x^3y^2+x^4y^2的值
若X^2+Y^2+2X-6Y+10=0,先化简X+Y分之Y^2,分之X-Y分之X-1
若|x+y-1|+(x-y-2)²=0,求代数式(x+2y)(x-2y)-(2x-y)(-y-2x)的值.
若3x-5y=0,则x+y/x=(),x-y/y=(),2x-3y/2x+3y=( )
若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值
{4x-3y-10=0 3x-2y=0,{3x-4(x-y)=2 2x-3y=1,{2(x+y)-(x-y)=3 (x+y)-2(x-y)=1
若实数x,y满足x²+y²-10x-2y+26=0 ,求根号下x²y²的值
若实数x,y满足x²+y²-10x-2y+26=0,求√x²y²
(X,Y) f(x,y)={12y^2,0
已知x>0,Y>0,如何证x^2/y+y^2/x>=x+y