若x^2-4x+y^2-10y+29=0,求x^2y^2+2x^3y^2+x^4y^2的值
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若x^2-4x+y^2-10y+29=0,求x^2y^2+2x^3y^2+x^4y^2的值若x^2-4x+y^2-10y+29=0,求x^2y^2+2x^3y^2+x^4y^2的值若x^2-4x+y^
若x^2-4x+y^2-10y+29=0,求x^2y^2+2x^3y^2+x^4y^2的值
若x^2-4x+y^2-10y+29=0,求x^2y^2+2x^3y^2+x^4y^2的值
若x^2-4x+y^2-10y+29=0,求x^2y^2+2x^3y^2+x^4y^2的值
x^2-4x+y^2-10y+29=x^2-4x+4+y^2-10y+25=(x-2)^2+(y-5)^2=0,
所以x=2,y=5.
代入x^2y^2+2x^3y^2+x^4y^2
得原式=900.
x=2
y=5
x^2y^2+2x^3y^2+x^4y^2=900
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