(x-y+2z)^2-(x-2y-3z)^2因式分解
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/13 03:30:13
(x-y+2z)^2-(x-2y-3z)^2因式分解(x-y+2z)^2-(x-2y-3z)^2因式分解(x-y+2z)^2-(x-2y-3z)^2因式分解平方差原式=[(x-y+2z)+(x-2y-
(x-y+2z)^2-(x-2y-3z)^2因式分解
(x-y+2z)^2-(x-2y-3z)^2
因式分解
(x-y+2z)^2-(x-2y-3z)^2因式分解
平方差
原式=[(x-y+2z)+(x-2y-3z)][(x-y+2z)-(x-2y-3z)]
=(2x-3y-z)(y+5z)
(x-y+2z)^2-(x-2y-3z)^2
=[(x-y+2z)-(x-2y-3z)][(x-y+2z)+(x-2y-3z)]
=(x-y+2z-x+2y+3z)(x-y+2z+x-2y-3z)
=(x-x+2y-y+2z+3z)(x+x-y-2y+2z-3z)
=(y+5z)(2x-3y-z)
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
2(x+y)(x+y-z)+3(y-z)(x+y-z)
化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(x-2z+y)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z)
计算:(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(x+y-2z)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z)
(x-3y+2z)(x+3y-2z)
(x-2y+3z)(x+2y-3z)
(2y-x-3z)(-x-2y-3z)
计算:x^2/(x-y)(x-z)+y^2/(y-x)(y-z)+z^2/(z-x)(z-y)
2(x+y-z)-3(x-y+z)-5(x+y-z)+6(x-y+z) 计算
证明 :x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0
化简-(-3x-y+2z)-{-x+【4x-(x-y-z)-3x+2z}
化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(xy-2z)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z)速速回答
(x+3y-2z)(x-3y-2z)-(x+3y-2z)^2
x+2y=3x+2z=4y+z 求x:y:z
x/2=y/3=z/5 x+3y-z/x-3y+z
x+y/2=z+x/3=y+z/4 x+y+z=27
数学--整式运算4(x-y+z)-2(x+y-z)-3(-x-y-z)