x+y/2=z+x/3=y+z/4 x+y+z=27
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x+y/2=z+x/3=y+z/4x+y+z=27x+y/2=z+x/3=y+z/4x+y+z=27x+y/2=z+x/3=y+z/4x+y+z=27x+y/2=z+x/3=y+z/4①x+y+z=2
x+y/2=z+x/3=y+z/4 x+y+z=27
x+y/2=z+x/3=y+z/4 x+y+z=27
x+y/2=z+x/3=y+z/4 x+y+z=27
x+y/2=z+x/3=y+z/4 ①
x+y+z=27 ②
①×12得:12x+6y=12z+4x=12y+3z
故:
12x+6y=12z+4x ③
12z+4x=12y+3z ④
由③得 x=(6z-3y)/4
把 x=(6z-3y)/4代入②和④中:
(6z-3y)/4+y+z=27
12z+4×(6z-3y)/4=12y+3z
解上述二元一次方程组得:y=z=108/11
将y=z=108/11代入②中得:x=81/11
∴x=81/11
y=108/11
z=108/11
好难啊!
x+y/2=z+x/3=y+z/4 x+y+z=27
x+2y=3x+2z=4y+z 求x:y:z
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
2x+z=10 x+y-z=4 3x-y-z=0
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
证明 :x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0
(x+y-z)(x-y+z)=
x/2=y/3=z/5 x+3y-z/x-3y+z
若x+y+z=3y=2z,则x/x+y+z=?
若x,y,z成等差数列,则(z-x)^2-4(x-y)(y-z)=
(x*x+2)(y*y+4)(z*z+8)=64xyz,求x,y,z
设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值
x/2=y/3=z/4,则x+2y-z/z=?
(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊
x+y=5 2x+3y-z=9 x-y+z=4
{2x+y=10 {x-y+z=4 {3x-y-z=0