(x*x+2)(y*y+4)(z*z+8)=64xyz,求x,y,z

(x*x+2)(y*y+4)(z*z+8)=64xyz,求x,y,z (4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=? (4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊 (x-y)^2+4z(x-y)+4z^2 12x^2y^3z-8x^3y^2z+4x^2y 化简-(-3x-y+2z)-{-x+【4x-(x-y-z)-3x+2z} x+2y=3x+2z=4y+z 求x:y:z x+y/2=z+x/3=y+z/4 x+y+z=27 数学--整式运算4(x-y+z)-2(x+y-z)-3(-x-y-z) 若x,y,z成等差数列,则(z-x)^2-4(x-y)(y-z)= 化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+（z-y)(x-y)/(x-2z+y)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z) 计算:(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(x+y-2z)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z) 计算:x^2/(x-y)(x-z)+y^2/(y-x)(y-z)+z^2/(z-x)(z-y) x:y:z=3:4:5 2x-3y+2z=8 x-y-2z=? 2x+y+z=4 x+2y+z=8 x +y+2z=24 三元一次方程 2x+y+z=4 x+2y+z=8 x+y+2z=12 (4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian x+y+z=-1 4x-2y+3z=5 y-z=8-2x