(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/21 21:14:45
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=?kuaihuajian(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=?kuaihuaji
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
huajian
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]
=4x-2y-z-5x[6y-(x+y)]+x-(3y-10z)
=4x-2y-z-30xy+5x²+5xy+x-3y+10z
=5x-5y+9z-25xy+5x²
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊
(x*x+2)(y*y+4)(z*z+8)=64xyz,求x,y,z
已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..
x:y:z=3:4:5 2x-3y+2z=8 x-y-2z=?
x+y+z=-1 4x-2y+3z=5 y-z=8-2x
x+y+z=51 4x+8y+5z=300 x+y+2z=67
设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值
已知关于x y z的方程组2x-3y+5z=7 x+2y-3z=8,则4x+y-z=
{(z+y)(x-y)-(x-y)的2次方+2y(x-y)}除以4y
解三元一次方程组1、x+y-z=4 2x-y+z=5 x-3y+z=-2 2、y+2z=-2 3x+y-4z=1 2x-y+2z=8 3、x-2y+z=-1 x+y+z=2x+2y+3z=-1
12x^2y^3z-8x^3y^2z+4x^2y
1.(x+y-z)+(x-y+z)-(x-y-z) 2.2x-(3x-2y+3)-(5y-2)
x+y=5 2x+3y-z=9 x-y+z=4
{x+y+z=12 x+2y+5z=22 x=4y
化简(x+Y)^2(y+z-x)(z+x-y)+(x-y)^2(x+y+z)(x+y-z)
计算题(x+y)^2(y+z-x)(z+x-y)+(x-y)^2(x+y+z)(x+y-z).