x+y=5 2x+3y-z=9 x-y+z=4
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x+y=52x+3y-z=9x-y+z=4x+y=52x+3y-z=9x-y+z=4x+y=52x+3y-z=9x-y+z=4X=3Y=2Z=3x13/3y2/3z1/3
x+y=5 2x+3y-z=9 x-y+z=4
x+y=5 2x+3y-z=9 x-y+z=4
x+y=5 2x+3y-z=9 x-y+z=4
X=3Y=2Z=3
x13/3y2/3z1/3
已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..
x+y=5 2x+3y-z=9 x-y+z=4
x/2=y/3=z/5 x+3y-z/x-3y+z
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
解方程组 x+y+z=5 2x-y-z=4 3x-2y-z=9
2x+3y-z=9,x+y+z=15,5x-4y-z=0
X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z
设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值
三元一次方程组,1.x-2y+z=9 2x+y+3z=10 3x+2y1.x-2y+z=92x+y+3z=103x+2y-z2.3x-5y+2z=14x+5y-z=5X-5y+3z=-23.7x+2y-z=76x-y+z=74x+3y+z=94.4x+3y-2z=-75x-6y+z=12x+z=-25.2x+3y-4z=-23x-2y+5z=262x+5z=31
9x-5y+z=-6 9x+y-2z=3 -9x+3y-5z=0 求x y z
6x+3y-2z=108,9x+7y-3z=212,3x-2y+5z=38,求x,y,z
三元一次方程解 1.{x+y-z=5 {3x+2y+z=2 {2x-2y+z=-31.{x+y-z=5 2.{9x-5y+x=-6 3.{x-y=3 4.{x+y=3 5.{4x-2y+z=7{3x+2y+z=2 {9x+y-2z=3 {x+z=7 {y+z=4 {2x-y-3z=28{2x-2y+z=-3 {-9x+3y-5z=0 {y-z=6 {z+x=5 {x+y-2z=13
已知x/y+z=y/x+z=z/x+y,分式(x+2y+3z)/(2x+5y-2c)有意义时的值
x+y+z=35 2x-y=5 y/3=z/2 求x,y,z
(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊