X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z

若X/10=Y/8=Z/9则X+Y+Z/Y+Z=? X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z 若x除以10=y除以8=z除以9,则x+y+z除以y+z 解方程组：{x(x+y+z)=6 {y(x+y+z)=9 {z(x+y+z)=10 x+y=8 y+z=12 x+z=10 x+y+z= x+y=8 y+z=12 x+z=10 x+y+z= (x+y-z)(x-y+z)= 已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX.. 已知x+y=8,y+z=12,x+z=10,则x+y+z=? 若x+y=8 y+z=12 x+z=10 则x+y+z =多少 已知x+y=8,x+z=12,x+z=10,则x+Y+z等于几? (x+y+z)÷10=x+1.1 y+x=z-80+y-1 z-y=8x+y+8 x+z÷y=? (4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=? x/10 = y/8 =z/9 求x+2y+3z/y-5z X+Y+Z=? x/y=(x+z)/(y+z)y/z=(x+y)/(x+z) 已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=? (4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊