12x^2y^3z-8x^3y^2z+4x^2y

12x^2y^3z-8x^3y^2z+4x^2y x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少, (4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=? 3x-y+z=4,2z+3y-z=12,x+y+z=6的解 化简-(-3x-y+2z)-{-x+【4x-(x-y-z)-3x+2z} x+2y=3x+2z=4y+z 求x:y:z x+y/2=z+x/3=y+z/4 x+y+z=27 数学--整式运算4(x-y+z)-2(x+y-z)-3(-x-y-z) (4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊 求化简(x+3y+2z)(x-3y+6z)(x+3y+4z-2z)(x-3y+4z+2z) 已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX.. X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z 因式分解Z^2(x-y)-4(x-y)-3Z(y-z) 如果x+4/3=y+z/2=z+8/4,且x+y+z=12,求x,y,z的值. 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z ①x+y+z=6 3x-y+2z=12 x-y-3z=-4 ②x+y-z=2 4x-2y+3y+8=0 x+3y-2z-6=0③x/3=y/2 y/4=z/5 x+y+z=60三元一次方程 x:y:z=3:4:5 2x-3y+2z=8 x-y-2z=?