|2x-y-2|+(2x+y+10)²=0,则,( )(A){x=2 (B){x=-2 (C){x=2 (D){x=-2y=6 y=-6 y=-6 y=6
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|2x-y-2|+(2x+y+10)²=0,则,()(A){x=2(B){x=-2(C){x=2(D){x=-2y=6y=-6y=-6y=6|2x-y-2|+(2x+y+10)²=
|2x-y-2|+(2x+y+10)²=0,则,( )(A){x=2 (B){x=-2 (C){x=2 (D){x=-2y=6 y=-6 y=-6 y=6
|2x-y-2|+(2x+y+10)²=0,则,( )
(A){x=2 (B){x=-2 (C){x=2 (D){x=-2
y=6 y=-6 y=-6 y=6
|2x-y-2|+(2x+y+10)²=0,则,( )(A){x=2 (B){x=-2 (C){x=2 (D){x=-2y=6 y=-6 y=-6 y=6
|2x-y-2|和(2x+y+10)²都是非负数,所以都等于0,
{2x-y-2 =0
2x+y+10 =0,所以x=-2 ,y=-6,选B
|2x-y-2|+(2x+y+10)²=0
则|2x-y-2|=0
(2x+y+10)²=0
2x-y=2 1式
2x+y+10=0 2式
2式-1式
2y=-12
y=-6
所以x=-2
选b
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