y=1-3cos^2(x/3+π/6)周期是
来源：学生作业帮助网 编辑：六六作业网 时间：2024/12/23 19:32:40
y=1-3cos^2(x/3+π/6)周期是y=1-3cos^2(x/3+π/6)周期是y=1-3cos^2(x/3+π/6)周期是f(x)=3cos(1/2x－π/6)x∈R(1)f(x)=Acos
y=1-3cos^2(x/3+π/6)周期是
y=1-3cos^2(x/3+π/6)周期是
y=1-3cos^2(x/3+π/6)周期是
f(x)=3cos(1/2x－π/6) x∈R (1)f(x)=Acos(wx－π/6)x T=21/2x－π/6=2kπ x=π/3 4kπ解集是{x|x=π/3 4kπ}
y=cos(π/3-x)cos[π/2（x-1)]判断奇偶性y=cos(π/3-x)cos(π/3+x)判断奇偶性
Sin x-sin y=2/3 cos x-cos y=1/2 求cos(x-y)
函数y=2cos(x-π/3)(π/6
y=3cos(2x-π/6)单调区间
【高中数学】已知cos(x+y)=1/3,cos(x-y)=2/3,且0
已知cos(x+y)=1/3,cos(x-y)+2/3,且0
y=3cos(2x+π/4) （2）y=2cos(x-π/6)的单调区间
y=(3/2)cos(1/2x-π/6)X∈R的周期 ,
求y=-3/2cos(1/2x-π/6)取得最值时x的范围.
y=-3/2cos(1/2x-π/6),x∈R的单调区间
1.y=sin(-X+π/6)2.y=cos(-2X+π/3)
cos(x-y/2)=-1/9,sin(x/2-y)=2/3,π/2
把函数y=cos(1/2x-π/6)进行怎样的变化得到y=2cos(x-π/3)
已知x属于[-派/3,2派/3],求（1）函数y=cos^2x-2sinx的值域（2）函数y=3cos(2x-派/6)cos^2x是cos的平方x
若cos(x+y)cos(x-y)=1/3,则cos^x-sin^y=?^为平方
求下列函数导数y=cos（π/3-x）y=e^3xy=In(3-x)y=cos^3(1-2x)
函数y=cos(3π/2-x)/cos(3π-x)最小正周期是
函数y=cos(3π/2-x)/cos(3π-x)最小正周期是：