已知sinx+siny=2sin(x+y)≠0,则tanx/2tany/2等于 是三角函数和差化积部分的
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已知sinx+siny=2sin(x+y)≠0,则tanx/2tany/2等于是三角函数和差化积部分的已知sinx+siny=2sin(x+y)≠0,则tanx/2tany/2等于是三角函数和差化积部
已知sinx+siny=2sin(x+y)≠0,则tanx/2tany/2等于 是三角函数和差化积部分的
已知sinx+siny=2sin(x+y)≠0,则tanx/2tany/2等于 是三角函数和差化积部分的
已知sinx+siny=2sin(x+y)≠0,则tanx/2tany/2等于 是三角函数和差化积部分的
sinx+siny=2sin(x+y)
2sin(x/2+y/2)cos(x/2-y/2)=4sin(x/2+y/2)cos(x/2+y/2)
cos(x/2-y/2)=2cos(x/2+y/2)
cos(x/2)cos(y/2)+sin(x/2)sin(y/2)=2cos(x/2)cos(y/2)-2sin(x/2)sin(y/2)
3sin(x/2)sin(y/2)=cos(x/2)cos(y/2)
tan(x/2)tan(y/2)=1/3
证明sin(x+y)sin(x-y)=sinx-siny
已知(sinx)2-(siny)2=m求sin(x y)sin(x-y)求sin(x+y)sin(x-y)
证明 [sin(2x+y)/sinx]-2cos(x+y)=siny/sinx
求证sin(2x+y)/sinx-2cos(x+y)=siny/sinx
求证:sin(2x+y)/sinx-2cos(x+y)=siny/sinx
已知sinx-siny=1/2,cosx-cosy=1/2,x、y均为锐角,求sin(x-y)
证明sin(x+y)sin(x-y)=(sinx)^2-(siny)^2.
求证:sin(2x+y)/sinx-2cos(x+y)=siny/sinx(2)已知5siny=sin(2x+y),求证:tan(x+y)=3/2 tanx
证明sinx+cos(x+y)siny/cosx-sin(x+y)siny=tan(x+y)
证明cosx(cosx-cosy)+sinx(sinx-siny)=2sin(x-y)/2
已知x,y,z属于(0,派/2),sin^2x+sin^2y+sin^2z=1,求(sinx+siny+sinz)/(cosx+cosy+cosz)的最大值
为什么sinx*cosy-cosx*siny=sin(x-y)
求函数z=sinx+siny+sin(x+y)(0
存在sin( x -y) = sinX-sinY吗
请问,如何证明sinx+siny=2*sin(x+y/2)*cos(x-y/2)
为什么sin(x+y) - sinx = 2cos(x+y/2)siny/2
求推导sinx-siny=2cos((x+y)/2)sin((x-y)/2)
求证sinx+siny=2sin(x+y)/2*cos(x-y)/2