Given m is a real number,and|1-m|=|m|+1,simplify an algebraic expression,then√m^2-2m+1=
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Givenmisarealnumber,and|1-m|=|m|+1,simplifyanalgebraicexpression,then√m^2-2m+1=Givenmisarealnumber,a
Given m is a real number,and|1-m|=|m|+1,simplify an algebraic expression,then√m^2-2m+1=
Given m is a real number,and|1-m|=|m|+1,simplify an algebraic expression,then√m^2-2m+1=
Given m is a real number,and|1-m|=|m|+1,simplify an algebraic expression,then√m^2-2m+1=
D
|1-m|=|m|+1得m=<0
题目的中文意思是：已知m是实数，且|1-m|=|m|+1，化简代数式√m^2-2m+1=
根据已知条件，两边平方，得到
1+m^2-2m=|m|^2+1+2|m|
所以-2m=|m|
因此m<=0
所以√m^2-2m+1=-m-2m+1=-3m+1
Given m is a real number,and|1-m|=|m|+1,simplify an algebraic expression,then√m^2-2m+1=
Given m is a real number,and|1-m|=|m|+1,simplify an algebraic expression,then√m^2-2m+1=A |m|-1 B -|m|-1 C m-1 D-m+1
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