若(2x+4)^2n+|x-2y|=0(n是正整数),求2(x^2y+3XY^2)-4(xy^2-1)-2x^2y-4的值

若集合P={y|y=x^+4x+6}M={y|y=2x+2/x,x>0}则M∩N 若方程组2x+y=n x+2y=3n+4中,若x+y＞0,则n的范围是?RT 若（2x+3Y-5)平方+|x-3y-4|=0,且n为奇数,则x的n次方y的n次方+2 已知x,y是实数,集合m{x,y已知x,y是实数,集合m={x,y/x,1},n={x^2,x+y,0}.若m=n,求x^2012+y^2012的值 若[-3(x+y)^m*(x-y)^2n]^2*[-(x+y)^2]=-a(x+y)^10*(x-y)^12-n,求m,n的值 若X^n=2,y^n=3,(x^2y^3)^n= 若x^my·4y^n-(2x)²y^4=0,则m+n=? 若x^my·4y^n-(2x）²y^4=0,则m+n=____ 证明不等式,非常难...证明:(1)x^4 - 3x^3 + 4x^2 - 3x + 1 >= 0; (2)(x^2n)(y^0) + (x^(2n-1))(y^1) + (x^(2n-2))(y^2) + .+ (x^2)(y^(2n-2)) + (x^1)(y^(2n-1)) + (x^0)(y^(2n)) >=0; 若1+2+3+...+n=a,求代数式(x^ny)(x^n-1y^2)(x^n-2y^3)...(x^2y^n-1)(xy^n) 若1+2+3+...+n=a,求代数式(x^ny)(x^n-1y^2)(x^n-2y^3)...(x^2y^n-1)(xy^n) 若1+2+3+...+n=55,求代数式(x^ny)(x^n-1y^2)(x^n-2y^3)...(x^2y^n-1)(xy^n) 已知集合M={(X,Y)Y=X-3},N={(X,Y)|2X-Y+4=0},那么M∩N= 已知集合M={（x,y)|y=-x^2+2x},N={(x,y)|y=2x^2-4x},则M∩N=? x^n*y*(-x^2y^m) m(x-y)^n+n(y-x)^2n因式分解 y=(x-1)(x-2)(x-3)(x-4)...(x-n) 若n是正整数,有理数x、y满足x+y分之一=0,则一定成立的是 A.x^2n+1+(1/y)^n=0 B.x^2n+1+(1/y)^2n+1=0C.x^2n+(1/y)^2n=0 D.x^n+(1/y)^2n=0