[log(5)8]*[log(32)5]+log(9)8/log(3)2
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/27 13:37:22
[log(5)8]*[log(32)5]+log(9)8/log(3)2[log(5)8]*[log(32)5]+log(9)8/log(3)2[log(5)8]*[log(32)5]+log(9)8
[log(5)8]*[log(32)5]+log(9)8/log(3)2
[log(5)8]*[log(32)5]+log(9)8/log(3)2
[log(5)8]*[log(32)5]+log(9)8/log(3)2
[log(5)8]*[log(32)5]+log(9)8/log(3)2
=log5(8)/log5(32)+log3^2 (2^3)/log3(2)
换底公式
=log32(8)+3/2*log3(2)/log3(2)
=log2^5 (2^3)+3/2
=3/5 log2(2)+3/2
=3/5+3/2
=6/10+15/10
=21/10
[log(5)8]*[log(32)5]+log(9)8/log(3)2
(log(2)125+log(2)25+log(8)5)*(log(125)2+log(25)4+log(5)8)
求值:(log(4)3+log(8)3)×(log(3)2+log(9)2)+log(2)(2^5)¼
log(x+5)=log(x)+log(2) log(8)+log(x)=log(24) 2log(x)=log(2x)+log(3)
求值:2log(角标3)2-log(角标3)32/9+log(角标3)8-5^log(角标5)3等于?
log(2)5,log(5)8比大小
log(3)2-log(3)32/9+log(3)16 - 5的2log(5)3次方
log(2)1/25乘以log(3)1/8乘以log(5)1/9
log(2.5)6.25 -log(5)8log(16)125-lg4-lg25求过程答案
log 5 ·log 20 +(lg2)²
log(8)a+log(4)b^2=5,log(8)b+log(4)a^2=7,求log(2)ab的值
计算:(1) log(2)(3)*log(3)(4)*log(4)(5)(2)log(2)(7)*log(√7)(8)
已知log(14)7=a log(14)5=b 用ab表示log(35)70=log(3)4*log(4)8*log(8)m=log(4)2 求m
log(x)4/5
如何计算2^log(2)*5^log(5)*2^log(5)*5^log(2) 的结果?
log(4)25-2log(4)10+log(4)5*log(5)16
log
log