2x^2-8y^2,x^2-4xy+4y^2的公因式
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/18 14:37:29
2x^2-8y^2,x^2-4xy+4y^2的公因式2x^2-8y^2,x^2-4xy+4y^2的公因式2x^2-8y^2,x^2-4xy+4y^2的公因式2x^2-8y^2=2(x^2-4y^2)=
2x^2-8y^2,x^2-4xy+4y^2的公因式
2x^2-8y^2,x^2-4xy+4y^2的公因式
2x^2-8y^2,x^2-4xy+4y^2的公因式
2x^2-8y^2
=2(x^2-4y^2)
=2(x+2y)(x-2y)
x^2-4xy+4y^2
=(x-2y)^2
所以是x-2y
x-2y
2x^2-8y^2=2(x-2y)(x+2y)
x^2-4xy+4y^2=(x-2y)^2
因式分解:12xy^2(y-x)+xy^3(x-y)+4x^2y(x-y)
化简:3x^2-[5xy-(x^y-3xy)+4x^2y-8xy]
(x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1)
计算:2xy/(x+y)².(x+y)/4y
(x^-4y^)/(x^+2xy+y^)/(x+2y)/(2x^+2xy)
因式分解 x-xy+3y-3x 2x+xy-y-4x+5y-6
诺x+y=6,xy=4 求(5x-4y-3xy)-(8x-y+2xy)
2x(x-y)+4xy(y-x) 因式分解2x(x-y)+4xy(y-x) 因式分解
(x^2+2xy+y^2-4xy)*(x^2-2xy+y^2+4xy)
计算(x^8-x^7y+x^5y^3-x^4y^4+x^3y^5-x^y^7+y^8)(x^2+xy+y^2)
已知x*x-4xy+4y*y=0 求[2x(x+y)-y(x+y)]/(4x*x-4xy+y*y)的值?
因式分解x^2(x-y)-4xy(x-y)-4y^2(y-x)
计算:4xy-(x+y)^2/xy(x+y)(x-y)÷x^2+xy-2y^2/x^2y+2xy^2
化简2(x²y+xy)-3(x²y-xy)-4x²y
计算:(1)8x^2y^2*(-3x/4y^5) (2)(x+y)^2/xy-y^2*(y-x)^2/xy+y^2
因式分解:x-4xy-2xy+8y等于?
[(X-2Y)^2-X(X-4Y)-8XY]÷4Y
(-3x^y+2xy)-( )=4x^+xy