A girl at the bottom of a 100m high cliff throws a tennis ball vertically upwards.A boy at the very top of the cliff drops a golf ball so that it hits the tennis ball while both ball are still in the air.Q1:With what speed is the tennis ball thrown s

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Agirlatthebottomofa100mhighcliffthrowsatennisballverticallyupwards.Aboyattheverytopofthecliffdropsag

A girl at the bottom of a 100m high cliff throws a tennis ball vertically upwards.A boy at the very top of the cliff drops a golf ball so that it hits the tennis ball while both ball are still in the air.Q1:With what speed is the tennis ball thrown s
A girl at the bottom of a 100m high cliff throws a tennis ball vertically upwards.A boy at the very top of the cliff drops a golf ball so that it hits the tennis ball while both ball are still in the air.
Q1:With what speed is the tennis ball thrown so that the golf ball strikes it at the top of its path?
Q2:What's the position of the tennis ball when the golf ball strikes it?

A girl at the bottom of a 100m high cliff throws a tennis ball vertically upwards.A boy at the very top of the cliff drops a golf ball so that it hits the tennis ball while both ball are still in the air.Q1:With what speed is the tennis ball thrown s
题目大意是:一个女孩在高为100米的高崖底部处垂直向上投出一个网球,一个小男孩在最顶端垂直向下释放一个高尔夫球,使两球能在空中相遇.
问题1:网球扔出时具有什么速度能使两球在网球到达最高处时相遇?
问题2:当两球相遇时,网球的位置?
(1) 设:网球掷出时的速度为v0,两球相遇时距离球抛出时间为t0
因为高尔夫球自由落体:所以加速度为g=9.8m/s(如果用10m/s的话也行,具体看题目要 求,没有要求的话两个都行,在这个题目中g对第一问无影响),网球只受地心引力作用所以加速度也为g=9.8m/s
由牛顿运动定理得:
相遇时:
网球:路程s1=v0t-1/2*gt*t(t

大意是:一女的在100米悬崖下向上垂直扔一网球,一男的再悬崖上放一高尔夫球,两球会在空中相撞。1.问网球的初速度是多少才能保证网球在其轨迹最高点与高尔夫球相撞?2.两球相撞的位置
1.网球s1=vt-1/2gt^2,高尔夫球s2=1/2gt^2,s1+s2=vt=100
网球轨迹最高点是速度为0,v-gt=0
g=10m/s^2, 由上两式可得初速度为v=根号100...

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大意是:一女的在100米悬崖下向上垂直扔一网球,一男的再悬崖上放一高尔夫球,两球会在空中相撞。1.问网球的初速度是多少才能保证网球在其轨迹最高点与高尔夫球相撞?2.两球相撞的位置
1.网球s1=vt-1/2gt^2,高尔夫球s2=1/2gt^2,s1+s2=vt=100
网球轨迹最高点是速度为0,v-gt=0
g=10m/s^2, 由上两式可得初速度为v=根号1000=10根号10m/s
2.代入v得s1=50m,相撞位置离地面50米

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