printf("%d",((x=4*5,x*5),x+20))

printf(%d,((x=4*5,x*5),x+20)) void main() {int x=4;if(x++>=5)printf(%d/n,x);else printf(%d/n,x--); printf(%d ,(x=5*6,x*4,x+5));这是什么意思? int x=20;printf(“%d”,0 int x=20;printf(“%d”,0 程序有个部分读不懂,#include void main(){int x,y,t;double a;float b;int c;scanf(%d %d,&x,&y);c=b=a=20/3;t=(x%y,x/y);printf(%d %d ,x--,--y); printf(%d ,t); printf(%d ,(x=5*6,x*4,x+5));printf(%f %f %f ,c,b,a);}中的t=(x%y,x/y)和 int x=3,y=4; printf(%d,%d,(x.y),(y,x)); main() { int a=5,b=4,x,y; x=a++*a++*a++; printf(“a=%d,x=%d ”,a,x); y=--b*--b*--b; printf(“b=%d, X++;Y++;printf(x=%d,y=%d,x,. 以下程序输出的结果是 main() {int x; x=-3+4%6/5； printf（%d,x）； } { int a[]={1,2,3,4,5,6}; int*p; p=a; printf(%d ,*p); printf(%d ,*(++p)); printf(%d ,*++p);{ int a[]={1,2,3,4,5,6};int*p;p=a;printf(%d ,*p);printf(%d ,*(++p));printf(%d ,*++p);printf(%d ,*(p--));P+=3;printf(%d%d,*p,*(a+3));}求 #include main() { int x; scanf(%d,x-5); if(x>15)printf(%d,x-5); if(x>10)printf(%d, if(a!=0) printf(%d ,x); else printf(%d , int x,y; x=13; y=5; {printf(%d,x%=(y/=2)); # include void main( ) { int x = 4 ; do { printf( %d ,x-- ) ; } while( x ) ; } printf(%d,%d ,a+b!=a-b,x printf(%d,%d ,a+b!=a-b,x int x=20; printf(%d ,x);呵呵