1.求三角函数值:⑴sin(—(43π)/6) ⑵cos(—(83π)/6)⑶tan(—(41π)/3)⑷cos((11π)/4)⑸sin930°2.化简:⑴【Cos(x—π) tan(x—2π) tan(2π—x)】/【sin(π+x)】⑵((sin^2 )(—x))—tan(360°—x) *tan(—x)—sin(180°
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1.求三角函数值:⑴sin(—(43π)/6)⑵cos(—(83π)/6)⑶tan(—(41π)/3)⑷cos((11π)/4)⑸sin930°2.化简:⑴【Cos(x—π)tan(x—2π)tan(
1.求三角函数值:⑴sin(—(43π)/6) ⑵cos(—(83π)/6)⑶tan(—(41π)/3)⑷cos((11π)/4)⑸sin930°2.化简:⑴【Cos(x—π) tan(x—2π) tan(2π—x)】/【sin(π+x)】⑵((sin^2 )(—x))—tan(360°—x) *tan(—x)—sin(180°
1.求三角函数值:⑴sin(—(43π)/6) ⑵cos(—(83π)/6)
⑶tan(—(41π)/3)
⑷cos((11π)/4)
⑸sin930°
2.化简:
⑴【Cos(x—π) tan(x—2π) tan(2π—x)】/【sin(π+x)】
⑵((sin^2 )(—x))—tan(360°—x) *tan(—x)—sin(180°—x) cos(360°—x) tan(180°+x)
1.求三角函数值:⑴sin(—(43π)/6) ⑵cos(—(83π)/6)⑶tan(—(41π)/3)⑷cos((11π)/4)⑸sin930°2.化简:⑴【Cos(x—π) tan(x—2π) tan(2π—x)】/【sin(π+x)】⑵((sin^2 )(—x))—tan(360°—x) *tan(—x)—sin(180°
你这题真够长的!看图,放大了.
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1.求三角函数值:⑴sin(—(43π)/6)⑵cos(—(83π)/6) ⑶tan(—(41π)/3) ⑷cos((11π)/4) ⑸sin930° 2.化简: ⑴【Cos(x—π) tan(x—2π) tan(2π—x)】/【sin(π+x)】 ⑵((sin^2 )(—x))—tan(360°—x) *tan(—x)—sin(18
1.求三角函数值:⑴sin(—(43π)/6) ⑵cos(—(83π)/6)⑶tan(—(41π)/3)⑷cos((11π)/4)⑸sin930°2.化简:⑴【Cos(x—π) tan(x—2π) tan(2π—x)】/【sin(π+x)】⑵((sin^2 )(—x))—tan(360°—x) *tan(—x)—sin(180°
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