先化简,再求值:[(x²-2x+1)分之x]÷[(x²-1)分之(x+1)+1],其中x=根号2+1

来源：学生作业帮助网编辑：六六作业网时间：2025/02/04 04:53:18

先化简,再求值:[(x²-2x+1)分之x]÷[(x²-1)分之(x+1)+1],其中x=根号2+1先化简,再求值:[(x²-2x+1)分之x]÷[(x²-1)

先化简,再求值:[(x²-2x+1)分之x]÷[(x²-1)分之(x+1)+1],其中x=根号2+1
先化简,再求值:[(x²-2x+1)分之x]÷[(x²-1)分之(x+1)+1],其中x=根号2+1

:[(x²-2x+1)分之x]÷[(x²-1)分之(x+1)+1],其中x=根号2+1
=[x/(x-1)²]÷[(x+1)/(x-1)(x+1)+1]
=[x/(x-1)²]÷[1/(x-1)+1]
=[x/(x-1)²]÷[(1+x-1)/(x-1)]
=[x/(x-1)²]÷[x/(x-1)]
=1/(x-1)
=1/(√2+1-1)
=1/(√2)
=(√2)/2