Please help me to solve this question with working.Thank you.Candle A and candle B are of the same length.Candle A,which is broader,can burn for 5 hours while Candle B,the thinner candle,can burn for 4 hours.If both candles are lighted at the same ti
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Please help me to solve this question with working.Thank you.Candle A and candle B are of the same length.Candle A,which is broader,can burn for 5 hours while Candle B,the thinner candle,can burn for 4 hours.If both candles are lighted at the same ti
Please help me to solve this question with working.Thank you.
Candle A and candle B are of the same length.Candle A,which is broader,can burn for 5 hours while Candle B,the thinner candle,can burn for 4 hours.If both candles are lighted at the same time,how long does it take for candle A to be twice as long left as candle
Please help me to solve this question with working.Thank you.Candle A and candle B are of the same length.Candle A,which is broader,can burn for 5 hours while Candle B,the thinner candle,can burn for 4 hours.If both candles are lighted at the same ti
蜡烛A和蜡烛B一样长,蜡烛A可以燃5小时,蜡烛B只能燃4小时.如果两根蜡烛一起点燃,问多长时间以后,蜡烛A是蜡烛B的两倍长.
设时间=x
则有 2*（1-x/4）=1-x/5 解得x = 10/3
所以时间为3小时20分
列一次方程易得三分之十时
Imagine the length of these two candles is 1 and it takes X hours for candle A to be twice as long left as candle B.So after X hours candle A is left 1-X/5 long and candle B is left 1-X/4 long.At this time,candle A is twice longer than candle B, so (1-X/5)/(1-X/4)=2. We can get the result X=10/3 h.