如图,AE=AC,AD=AB,角EAC=角DAB,求证:ED=CA

如图,角B=角E,角BAD=角EAC,AC=AD,求证AB=AE 如图,AB=AC,AD=AE,CD=BE,求证,角DAB=角EAC 如图,AE=AC,AD=AB,角EAC=角DAB,求证:ED=CA 如图,已知AB⊥AC,AD⊥AE,AB=AC,AD=AE,求证△EAC≌△DAB 如图,已知AE=AC,AD=AB,∠EAC=∠DAB,求证:∠D=∠B 如图,∠B=∠E,∠BAD=∠EAC,AC=AD,求证:AB=AE 如图已知ab=ad,ac=ae∠bad=∠eac是说明bc=de 如图,AB=AC,AD = AE,CD=BE．求证：∠DAB=∠EAC． 如图：AD=AE,∠DAB=∠EAC,AM=AN,求证：AB=AC 如图,已知AB=AC,AD=AE,∠DAB=∠EAC,求证:DC=EB 真么写已知如图ab=ac ad=ae ab dc相交于点m ac be相交于点n,角bab=角eac 求角am=an已知如图ab=ac ad=ae ab dc相交于点m ac be相交于点n,角bab=角eac求角am=an 如图△abe中ab=ae,ad=ac,角bad=角eac,bc,ed交与点o 如图,己知三角形ABC和三角形ADE都是等腰三角形,AB=AC,AD=AE,且角DAB=角EAC,则DE和bc平行 如图,已知角EAC=角EDC,要证明ABC全等于ADE,还要补充的条件是A、AB=AD AC=AEB.AB=AD BC=DEC.AC=AE BC=DE 已知:如图,角EAC是三角形ABC的外角,AD平分角EAC,且AD平行于BC.求证：AB=AC. 如图,△ABC中,AB=AC,AD是角EAC的平分线.求证:AD‖BC如图,△ABC中,AB=AC,AD是角EAC的平分线.求证:AD‖BC 如图,已知AB=AC,AD=AE,AB与DC相交于点M,∠DAB=∠EAC,AM=5,求AN的长 如图,在△ABE中,AB=AE,AD=AC,角BAD=角EAC,BC,DE交于点O.请问这道题怎如图,在△ABE中,AB=AE,AD=AC,角BAD=角EAC,BC,DE交于点O. 请问这道题怎么写