求值:cos(3π/8-θ)cos(5π/24-θ)+sin(π/8+θ)sin(7π/24+θ)学到三角恒等式的 诱导公式 那里求值:cos(3π/8-θ)cos(5π/24-θ)+sin(π/8+θ)sin(7π/24+θ)我算到一半算不下去了π是派(pai)哦...=2cos(3π/8-θ)cos(5π/24-θ) =

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/25 09:59:20
求值:cos(3π/8-θ)cos(5π/24-θ)+sin(π/8+θ)sin(7π/24+θ)学到三角恒等式的诱导公式那里求值:cos(3π/8-θ)cos(5π/24-θ)+sin(π/8+θ)

求值:cos(3π/8-θ)cos(5π/24-θ)+sin(π/8+θ)sin(7π/24+θ)学到三角恒等式的 诱导公式 那里求值:cos(3π/8-θ)cos(5π/24-θ)+sin(π/8+θ)sin(7π/24+θ)我算到一半算不下去了π是派(pai)哦...=2cos(3π/8-θ)cos(5π/24-θ) =
求值:cos(3π/8-θ)cos(5π/24-θ)+sin(π/8+θ)sin(7π/24+θ)
学到三角恒等式的 诱导公式 那里
求值:cos(3π/8-θ)cos(5π/24-θ)+sin(π/8+θ)sin(7π/24+θ)
我算到一半算不下去了
π是派(pai)哦...
=2cos(3π/8-θ)cos(5π/24-θ)
=cos(3π/8-θ-5π/24+θ)+cos(3π/8-θ+5π/24-θ)
只是搞不懂这两步之间怎么变过去的...我自己就做到=2cos(3π/8-θ)cos(5π/24-θ) 这步

求值:cos(3π/8-θ)cos(5π/24-θ)+sin(π/8+θ)sin(7π/24+θ)学到三角恒等式的 诱导公式 那里求值:cos(3π/8-θ)cos(5π/24-θ)+sin(π/8+θ)sin(7π/24+θ)我算到一半算不下去了π是派(pai)哦...=2cos(3π/8-θ)cos(5π/24-θ) =
注意关系3π/8-θ=π/2-(π/8+θ)
5π/24-θ=π/2-(7π/24+θ)
所以原式=cos(3π/8-θ)cos(5π/24-θ)+cos(3π/8-θ)sin(7π/24+θ)
=cos(3π/8-θ)cos(5π/24-θ)+cos(3π/8-θ)cos(5π/24-θ)
=2cos(3π/8-θ)cos(5π/24-θ)
=cos(3π/8-θ-5π/24+θ)+cos(3π/8-θ+5π/24-θ)
=cosπ/6+cos(7/12π-2θ)
这是积化合差公式
cosA*cosB=1/2[cos(A-B)+cos(A+B)]

cos(3π/8-θ)cos(5π/24-θ)+sin(π/8+θ)sin(7π/24+θ)
=cos[π/2-(π/8+θ)]cos[π/2-(7π/24+θ)]+sin(π/8+θ)sin(7π/24+θ)
=sin(π/8+θ)sin(7π/24+θ)+sin(π/8+θ)sin(7π/24+θ)
=2sin(π/8+θ)sin(7π/24+θ)
=2*(-1...

全部展开

cos(3π/8-θ)cos(5π/24-θ)+sin(π/8+θ)sin(7π/24+θ)
=cos[π/2-(π/8+θ)]cos[π/2-(7π/24+θ)]+sin(π/8+θ)sin(7π/24+θ)
=sin(π/8+θ)sin(7π/24+θ)+sin(π/8+θ)sin(7π/24+θ)
=2sin(π/8+θ)sin(7π/24+θ)
=2*(-1/2)[cos(π/8+θ+7π/24+θ)-cos(π/8+θ-(7π/24+θ))
=-[cos(5π/12+2θ)-cos(-π/6)]
=cos(π/6)-cos(5π/12+2θ)
=√3/2-cos(5π/12+2θ)

收起