2(sin a)^2+(2sin a*cos a)/(1+tan a)=k试用k表示sin a-cos aa∈(π/4,π/2)
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2(sina)^2+(2sina*cosa)/(1+tana)=k试用k表示sina-cosaa∈(π/4,π/2)2(sina)^2+(2sina*cosa)/(1+tana)=k试用k表示sina
2(sin a)^2+(2sin a*cos a)/(1+tan a)=k试用k表示sin a-cos aa∈(π/4,π/2)
2(sin a)^2+(2sin a*cos a)/(1+tan a)=k
试用k表示sin a-cos a
a∈(π/4,π/2)
2(sin a)^2+(2sin a*cos a)/(1+tan a)=k试用k表示sin a-cos aa∈(π/4,π/2)
是不是前面整个是分子?
[2sin²a+2sinacosa]/(1+sina/cosa)=k
2sina(sina+cosa)/[(sina+cosa)/cosa]=k
2sinacosa=k
1-2sinacosa=1-k
sin²a+cos²a-2sinacosa=1-k
(sina-cosa)²=1-k
所以sina-cosa=±√(1-k)
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