∫dx/[cos^2(2x+兀/4)]
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∫dx/[cos^2(2x+兀/4)]∫dx/[cos^2(2x+兀/4)]∫dx/[cos^2(2x+兀/4)]哈哈哈你的pi写的太好玩了∫dx/[cos^2(2x+π/4)]=∫dx/[1/2co
∫dx/[cos^2(2x+兀/4)]
∫dx/[cos^2(2x+兀/4)]
∫dx/[cos^2(2x+兀/4)]
哈哈哈你的pi写的太好玩了
∫dx/[cos^2(2x+π/4)]
=∫dx/[1/2cos(4x+π/2)+1/2]
=∫dx/[-1/2sin(4x)+1/2]
=1/8*cos(4x)+C (C为常数)
∫dx/[cos^2(2x+兀/4)]
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