求y=sin(2x+派/4)+cos(2x-派/4)的最小周期

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求y=sin(2x+派/4)+cos(2x-派/4)的最小周期求y=sin(2x+派/4)+cos(2x-派/4)的最小周期求y=sin(2x+派/4)+cos(2x-派/4)的最小周期y

求y=sin(2x+派/4)+cos(2x-派/4)的最小周期
求y=sin(2x+派/4)+cos(2x-派/4)的最小周期

求y=sin(2x+派/4)+cos(2x-派/4)的最小周期
y=sin(2x+π/4)+cos(2x-π/4)=√2/2(sin2x+cos2x)+√2/2(cos2x+sin2x)=√2(sin2x+cox2x)=2sin(2x+π/4)
最小周期T=π