△ABC的三边a,b,c满足a^2-1/3b^2=1/4c^2,则∠C=

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△ABC的三边a,b,c满足a^2-1/3b^2=1/4c^2,则∠C=△ABC的三边a,b,c满足a^2-1/3b^2=1/4c^2,则∠C=△ABC的三边a,b,c满足a^2-1/3b^2=1/4

△ABC的三边a,b,c满足a^2-1/3b^2=1/4c^2,则∠C=
△ABC的三边a,b,c满足a^2-1/3b^2=1/4c^2,则∠C=

△ABC的三边a,b,c满足a^2-1/3b^2=1/4c^2,则∠C=
由题意,固定c(看做常数),则为双曲线方程,不在一条直线上三点均可以构成三角形,故要计算角C,条件不足.