(1)(x+2)^2-2(x+2)(x-2)(x-2)+(x-2)^2 (2)若2^m=3,4^m=8,则2^3m+2n=( )

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(1)(x+2)^2-2(x+2)(x-2)(x-2)+(x-2)^2(2)若2^m=3,4^m=8,则2^3m+2n=()(1)(x+2)^2-2(x+2)(x-2)(x-2)+(x-2)^2(2)

(1)(x+2)^2-2(x+2)(x-2)(x-2)+(x-2)^2 (2)若2^m=3,4^m=8,则2^3m+2n=( )
(1)(x+2)^2-2(x+2)(x-2)(x-2)+(x-2)^2 (2)若2^m=3,4^m=8,则2^3m+2n=( )

(1)(x+2)^2-2(x+2)(x-2)(x-2)+(x-2)^2 (2)若2^m=3,4^m=8,则2^3m+2n=( )
1.原式=x²+4x+4-2【(x²-4)(x-2)】+x²-4x+4
=2x²+4x+4-2x³+4x+2x²-8-4x+4
=4x²+2x³
2.∵2^m=3
4^m=8
∴2^3m=(2^m)^3
已知条件貌似没有n啊
∴原式=27+2n

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