Java X =1 Y =2 Z =3 为什么y+=z--/++x. 输出是6?Java X =1Y =2Z =3为什么y+=z--/++x. 输出是6?

Java X =1 Y =2 Z =3 为什么y+=z--/++x. 输出是6?Java X =1Y =2Z =3为什么y+=z--/++x. 输出是6? Java题:设 x = 1 ,y = 2 ,z = 3,则表达式 y+=z--/++x 的值是多少?(注:题上没说x,y,z类型) java位运算符问题.x=4.y=2,求Z. (1)Z=~X (2)Z=>Y java x=2,y=3,z=4,则表达式z*=y++*--x的值是( ).得16吗? 在java中如何解释z -= --y - x--;public class Test3{public static void main(String[] args){int x =2;int y = 3;int z = 4;z -= --y - x--;System.out.println(z);}} JAVA问题：int x =1,y=2,z =3;则语句 y+=z- - /++x的值是：为什么答案说是3.5呢,我也觉得是3啊! 一百钱买百鸡问题 java我的代码.class zw{int x,y,z;void zw1(){for(x=1;x x+y+z=6 x+2y+3z=14 y+1=z 已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值 已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值 若|x+3|+|y-2|+|2×z+1|=0求(x×z-y×z)(y-x+z)的值 已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) java 中 if (x--==1&&y++==1||z++==1)怎么理解! matlab解对数方程组[x,y,z]=solve('0.29744*x/(3+0.1*x+y+z)=(log10((3+x+y+z)/(3+0.1*x+y+z)))^2','0.79*x/(3+0.1*y+z)=(log10((3+x+y+z)/(3+0.1*x+y+z)*(3+y+z)/(3+0.1*y+z)))^2','1.25*x/(3+0.1*z)=(log10((3+x+y+z)/(3+0.1*x+y+z)*(3+y+z)/(3+0.*1y+z)*(3+z)/ y-=z--/++x 怎么运算 从左到右还是从右到左 这是java运算 java程序中运算式y+=z--/++x是怎么运算的? {x+y+z=1;x+3y+7z=-1;z+5y+8z=-2