解下列方程组:x^2+2xy+y^2=25 x^2-y^2-x-y=6

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解下列方程组:x^2+2xy+y^2=25x^2-y^2-x-y=6解下列方程组:x^2+2xy+y^2=25x^2-y^2-x-y=6解下列方程组:x^2+2xy+y^2=25x^2-y^2-x-y

解下列方程组:x^2+2xy+y^2=25 x^2-y^2-x-y=6
解下列方程组:x^2+2xy+y^2=25 x^2-y^2-x-y=6

解下列方程组:x^2+2xy+y^2=25 x^2-y^2-x-y=6
x^2+2xy+y^2=25
(x+y)^2=25
x+y=±5
当x+y=5时
x^2-y^2-x-y=6
(x-y)(x+y)-(x+y)=6
(x-y-1)(x+y)=6
5(x-y-1)=6
x-y-1=6/5
x-y=11/5
x+y=5
解得
x=18/5
y=7/5
当x+y=-5时
x^2-y^2-x-y=6
(x-y)(x+y)-(x+y)=6
(x-y-1)(x+y)=6
-5(x-y-1)=6
x-y-1=-6/5
x-y=-1/5
x+y=5
解得
x=12/5
y=13/5
所以x=18/5,y=7/5或x=12/5,y=13/5

x^2+2xy+y^2=25 x^2-y^2-x-y=6
(x+y)^2=25 (x+y)(x-y)-(x+y)=6
x+y=+-5 (x+y)(x-y-1)=6
x+y=5 x-y-1=6/5
x=3.6
y=1.4
x+y=-5 x-y-1=-1.2
x=-2.6
y=-2.4

这个题这样
第一个方程化为(x+y)^=25;
所以:x+y=5或-5,,所以x=5-y或x=-5-y再分别带入另一个方程得:
(5-Y)^-Y^-(5-Y)-Y=6得x=3.6和y=1.4或
(-5-y)^-Y^-(-5-y)-Y=6d得x=-7.4和y=-2.4