计算(-5)^2cot2/π+㏒2[3tan7π/4+10sin(-36π/60)]

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/24 20:26:26
计算(-5)^2cot2/π+㏒2[3tan7π/4+10sin(-36π/60)]计算(-5)^2cot2/π+㏒2[3tan7π/4+10sin(-36π/60)]计算(-5)^2cot2/π+㏒

计算(-5)^2cot2/π+㏒2[3tan7π/4+10sin(-36π/60)]
计算(-5)^2cot2/π+㏒2[3tan7π/4+10sin(-36π/60)]

计算(-5)^2cot2/π+㏒2[3tan7π/4+10sin(-36π/60)]
cot(π/2)=0,
tan(7π/4)=-tan(π/4)=-1,
sin(-60π/36)=sin(π/3)=√3/2,
∴3tan(7π/4)+10sin(-36π/60)=-3+5√3,
∴原式=1+log<2>(5√3-3).