y=cos(-pi／2x+pi/2)等于什么

y=cos(-pi／2x+pi/2)等于什么 y=sin(2x+Pi/3)+cos(Pi/6-2x)周期为 函数y=sin(pi/2+x)cos(pi/6+x)的最大值 matlab rotate程序求大神修改t=0:pi/1000:3.5*pi;k=fix(2*t/pi)+1;x=0.5*sqrt(2)*cos(0.5*k*pi+0.25*pi)+k.*cos(t);y=0.5*sqrt(2)*sin(0.5*k*pi+0.25*pi)+k.*sin(t);h=plot(x,y,'r');m=pi:pi/20:4.5*pi;n=fix(2*m/pi)-1;x0=2*cos(1.25*pi);y0=2*sin(1.25*pi);x2= matlab三维图程序：[X,Y]=meshgrid([200:2:300],[-pi/4:pi/100:pi/4]);M=-pi/4:pi/100:pi/4;f=sqrt(1-((1600+(X.*cos(M+pi/4)-0.707*X+40*sin(Y)).^2+(X.*sin(M+pi/4)-0.707*X-40*cos(Y)).^2-(0.707*X-40*sin(Y)).^2-(0.707*X+40*cos(Y)).^2)./(80*X)).^2);Z=(pi/ 为什么y=2sin(3x-3/4 *pi) 可以写成y=-cos(3x+3/4 *pi) matlab 中的一个简单画图题~画出z=sin(x/2)*cos(y)的曲面图,其中x 的21个值均匀分布在[-2*pi,2*pi],y的31个值均匀分布在[-pi,pi].>> x=-2*pi:4*pi/20:2*pi;>> y=-pi:2*pi/30:pi;>> z=sin(x/2).*cos(y);这里提示说：Matrix dimen lim(x->PI/2) COS X/(PI/2)-X matlab中y=(0.5+3.*sin(x*pi/180)./(1+x^2)).*cos(x*pi/180);哪里错了? MATLAB 下面这个代码错在哪里,还有就是什么时候定义函数加‘’syms x;x=-pi:0.01:pi;y=cos(tan(pi*x));subplot(2,2,1);plot(x,y)axis([-pi,-pi/2])subplot(2,2,2);plot(x,y)axis([-pi/2,0])subplot(2,2,3);plot(x,y)axis([0,pi/2])subplot(2,2 matlab参数方程绘图问题t=0:pi/1000:3*pi k=fix(2*t/pi)+1; y=0.5*sqrt(2)*sin(0.5*k*pi+0.25*pi)+k*sin(t); x=0.5*sqrt(2)*cos(0.5*k*pi+0.25*pi)+k*cos(t); plot(x,y) axis equal 为什么不能运行啊, Matlab u(x,t)=sin(5*pi*x)cos(5*pi*t)+2sin(7*pi*x)cos(7*pi*t) 其中0 已知x≥y≥z≥pi/12,x+y+z=pi/2,问cos x *sin y*cos z 的最大值和最小值 matlab中画三维离散点,参数s是关于点的变量,想利用colorbar实现每个点的颜色对应a的值,即4维图x=[];y=[];z=[];s=[];for a1=2/3*pi:pi/20:17/12*pi;for a2=-7/6*pi:pi/20:-1/2*pi;for a3=-1/6*pi:pi/20:2/3*pi;b1=cos(a1)*cos(a2)*cos 函数f(x)=sin^2(x+pi/12)+cos^2(x-pi/12)的最大值 f(2x)=sin (x+3*pi/4)+cos (x-pi/2), 2(sin^4 x + cos^4 x) =1 [ - pi ≤ x ≤ pi ] matlab中如何画图!x=-pi:0.1:pi; y=cos(x)/cos(2*x);plot(x.y)x=-pi:0.1:pi; y=cos(x)/cos(2*x);plot(x.y)Attempt to reference field of non-structure array 'x'.我的问题是：cos(x)/cos(2x)用matlab怎么画图?