2x^2+3y^2-8x+6y+11=0求x+y=
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2x^2+3y^2-8x+6y+11=0求x+y=2x^2+3y^2-8x+6y+11=0求x+y=2x^2+3y^2-8x+6y+11=0求x+y=配方:2(x-2)^2+3(y+1)^2=0两个非
2x^2+3y^2-8x+6y+11=0求x+y=
2x^2+3y^2-8x+6y+11=0求x+y=
2x^2+3y^2-8x+6y+11=0求x+y=
配方:2(x-2)^2+3(y+1)^2=0
两个非负数之和为0 则它们都为0
所以x-2=0
y+1=0
所以x=2
y=-1
x+y=1
由题中方程得
2(x-2)^2+3(y+1)^2=0
故要使等式成立就要x-2=0且y+1=0
故x=2,y=-1
故x+y=1
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y-3x=2,y-5x=4,y-7x=6,y-9x=8,y-11x=0方程组,无
【2(x-y)(x-y)(x-y)-8(x-y)(x-y)(x+y)+6y(x-y)(x-y)]/2(x-y)(x-y)
若x-y不等于0,2x-3y=0,则分式(10x-11y)/(x-y)的值是()?(10x-11y)/(x-y) =[(8x-8y)+(2x-3y)]/(x-y) =8为什么8X-8Y=8?(10x-11y)/(x-y)=[(8x-8y)+(2x-3y)]/(x-y)=8+(2x-3y)]/(x-y)=8+0=8
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3x+2=y 5x+4=y 7x+6=y 9x+8=y 11x=y
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