x*x+2x-y*y+6y-8=0,x+y不等于2,求x-y的值
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x*x+2x-y*y+6y-8=0,x+y不等于2,求x-y的值x*x+2x-y*y+6y-8=0,x+y不等于2,求x-y的值x*x+2x-y*y+6y-8=0,x+y不等于2,求x-y的值x
x*x+2x-y*y+6y-8=0,x+y不等于2,求x-y的值
x*x+2x-y*y+6y-8=0,x+y不等于2,求x-y的值
x*x+2x-y*y+6y-8=0,x+y不等于2,求x-y的值
x²+2x-y²+6y-8=0
x²+2x+1-(y²-6y+9)=0
(x+1)²-(y-3)²=0
(x+1)²=(y-3)²
x+1=±(y-3)
x+1=y-3
x-y=-4
x+1=-(y-3)
x+y=2(舍)
∴x-y=-4
﹣4
利用配方法可以将原式转化为X平方+2X+1－Y平方＋6Y-9＝0，又转化为（X+1）的平方减去（Y-3）的平方=0，再利用平方差公式转化为（X+1+Y-3）(X+1-Y+3)=0，整理得：（X+Y-2）(X-Y+4)=0,因为x+y不等于2，所以X-Y+4=0，所以x-y=-4.
x*x+2x-y*y+6y-8=0 （x+1)^2-(y-3)^2=0 (x+1+y-3) (x+1-y+3)=0
即（x+y-2)(x-y+4)=0 x-y+4=0 x-y=-4
(X+1)^2-(Y-3)^2=0
即X+1=Y-3或X+1=3-Y
得X-Y=-4或X+Y=2(舍)
所以X-Y=-4
x^2+2x-y^2+6y-8=0
配方可得（x+1)^2-(y-3)^2=0
（x+1)^2=(y-3)^2
即x+1=y-3或x+1=3-y
得x-y=-4或x+y=2 （舍）
答案即为x-y=-4
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