(log3^4+log5^2)(log2^9+log2^根号3)
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(log3^4+log5^2)(log2^9+log2^根号3)(log3^4+log5^2)(log2^9+log2^根号3)(log3^4+log5^2)(log2^9+log2^根号3)(log
(log3^4+log5^2)(log2^9+log2^根号3)
(log3^4+log5^2)(log2^9+log2^根号3)
(log3^4+log5^2)(log2^9+log2^根号3)
(log3^4+log5^2)(log2^9+log2^根号3)
=(lg4/lg3+lg2/lg5)(lg9/lg2+lg根号3/lg2)
=(2lg2*lg5+lg2*lg3)/lg3*lg5*(lg9+lg根号3)/lg2
=3/2(2lg5+lg3)/lg5
=3/2lg(25/3)/lg5
=3/2log5^(25/3)
(log3^4+log5^2)(log2^9+log2^根号3)
=（2log3^2+log5^2)(2log2^3+0.5log2^3)
=（2log3^2+log5^2)*2.5log2^3
=5+2.5log5^3
(log3^4+log5^2)(log2^9+log2^根号3)
求下列各式的值 1）log2 6+log2 3 2)lg5+lg2 3)log5 3+log5 三分之一 4）log3 5-log3 15
log2[log3[log5 125]]=?log2[log3[log5 125]]=?
(log2)和(log3)变成(log5)
log5[log2(log9/log3)]=?
运用对数换底公式化简log2(3)*log3(4)*log4(5)*log5(2),
log2 3 · log3 4 ·log4 5 ·log5 2 前面的是底数
帮忙换底化简下列:logaC*logcA .log2 3 * log3 4 * log4 5 * log5 2
高中数学题log2^25 * log3^4 * log5^9
log2 5*log5 81*log3 4+ln根号e
log2^25*log3^2倍根号2*log5^9=
log2^5*log3^2倍根号2*log5^9=
log3 25×log2 27×log5 2^-3=_____
2log5 10+log5 0.25= 2log5 25-3log2 64= log2(log2 16)= 已知lg2=a,lg3=b,求log3 4,log2 12
log的计算 ：log2（20）-log4（25)= log3(2)×log2（5）×log5（3）=?log2[log2(32)-log2(3÷4）+log2log的计算 ：log2（20）-log4（25)= log3(2)×log2（5）×log5（3）=?log2【log2(32)-log2(3÷4）+log2（6）】=?lgx+lg（x+15）=2 ..X
已知log2=a,log3=b,用a、b表示log5 72 (急~）1.已知log2=a,log3=b,用a、b表示log5 722.已知x=log2 5,求2^x+4^-x
化简:log2 2+log5 1-3^(2log9 5)+(3log3 5)^2+3^log3 2
log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=?