计算[x/﹙xy+y﹚]·[﹙x²+x﹚／x²y]

计算[x/﹙xy+y﹚]·[﹙x²+x﹚／x²y]
计算[x/﹙xy+y﹚]·[﹙x²+x﹚／x²y]

计算[x/﹙xy+y﹚]·[﹙x²+x﹚／x²y]
[x/﹙xy+y﹚]·[﹙x²+x﹚／x²y]
=[x/﹙y（x+1﹚]·[x﹙x+1﹚／x²y]
=1/y(x+1)*(x+1)/y
=1/y²
如果本题有什么不明白可以追问,

原式＝x/y﹙x＋y﹚·x﹙x＋y﹚/x²y＝1/y².

原式=[x/y(x+1)][x(x+1)/x²y]
=[x/y(x+1)][(x+1)/xy]
=x(x+1)/xy²(x+1)
=1/y²