卡诺图化简F(A,B,C,D)=∑m(3,5,7,8,9,10,11)+∑m(0,1,2,13,14,15)卡诺图化简F(A,B,C,D)=∑m(3,5,7,8,9,10,11)+∑d(0,1,2,13,14,15)
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卡诺图化简F(A,B,C,D)=∑m(3,5,7,8,9,10,11)+∑m(0,1,2,13,14,15)卡诺图化简F(A,B,C,D)=∑m(3,5,7,8,9,10,11)+∑d(0,1,2,1
卡诺图化简F(A,B,C,D)=∑m(3,5,7,8,9,10,11)+∑m(0,1,2,13,14,15)卡诺图化简F(A,B,C,D)=∑m(3,5,7,8,9,10,11)+∑d(0,1,2,13,14,15)
卡诺图化简F(A,B,C,D)=∑m(3,5,7,8,9,10,11)+∑m(0,1,2,13,14,15)
卡诺图化简F(A,B,C,D)=∑m(3,5,7,8,9,10,11)+∑d(0,1,2,13,14,15)
卡诺图化简F(A,B,C,D)=∑m(3,5,7,8,9,10,11)+∑m(0,1,2,13,14,15)卡诺图化简F(A,B,C,D)=∑m(3,5,7,8,9,10,11)+∑d(0,1,2,13,14,15)
F(A,B,C,D)=∑m(3,5,7,8,9,10,11)+∑d(0,1,2,13,14,15)
F=B+D
卡诺图化简 F(A,B,C,D) = ∑m(2,3,6,7,8,10,12,14),请画出卡诺图.
卡诺图化简F(A,B,C,D)=∑m(2,3,6,7,8,10,12,14)
用卡诺图化简 F(A,B,C)=∑m(1,2,3,4,5,6)
用卡诺图化简F(A,B,C,D)∑m(2,4,6,7,12,15)
用卡诺图化简逻辑函数 F(A,B,C,D)=∑m^4(0.2.8.10.11.12.13.14.15)
卡诺图化简F(A、B、C、D)=∑m(0、2、8、9、10、11、13、15)
利用卡诺图化简下列逻辑函数 F(A,B,C,D)=∑m(15,13,10,6,4)
请用卡诺图化简逻辑函数至最简与成式用卡诺图化简下列逻辑函数：F(A,B,C,D)=∑m(0,1,2,3,4,7,8,9,10,12,14,15）+∑d(5,13)
卡诺图化简F(A,B,C)=∑m(2,5,6)
卡诺图化简F(A,B,C,D)=∑m(0,2,3,7,8,10.,11,13,14)并写出最简或与式
用卡诺图化简F(A,B,C,D)=∑m(0,1,2,3,1,4,15) 真的急用
卡诺图化简F(A,B,C,D)=∑m(3,5,7,8,9,10,11)+∑m(0,1,2,13,14,15)卡诺图化简F(A,B,C,D)=∑m(3,5,7,8,9,10,11)+∑d(0,1,2,13,14,15)
用卡诺图化简下列函数F(A,B,C)= ∑m(0,6)+∑mx(2,5)F(A,B,C,D)= ∑m(0,1,3,4,6,7,14,15+)∑mx(8,9,11,12)
数字电路基础 公式化化简 F=(A+c)+(B+D)(B+d) 证明：AB(C+D)+D+d+(A+B)(b+c)=A+Bc+D卡诺图化简∑m(0,2,4,6,9,13)+∑d(1,3,7,10,11,14,15)要有图喔卡诺图要有图 符文要求的会追加分化简：F=(A+c)(B+D)(B+d) 第一个c和最
用卡诺图化简下列逻辑函数:F(A,B,C,D)=∑m(2,4,7,8)+∑d(10,11,12,13,14,15)
卡诺图化简F(A,B,C,D)=∑m(0,1,4,9,12,13)+∑d(2,3,6,10,11,14)想求证下答案是不是 A'B'+BD'+AC'D
用卡诺图化简F(A,B,C,D)=∑m(0,1,5,7,8,14,15)+∑d(3,9,12)答案给的是A'D+B'C'+ABC+AC'D'但是我觉得 卡诺图 的左下角那两个 约束项可以看成 就答案一共三项?
6.利用卡诺图化简逻辑函数F（A、B、C、D）=∑m^4(10,11,12,13,14,15)