tan(α+π/4)化简
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tan(α+π/4)化简tan(α+π/4)化简tan(α+π/4)化简tan(α+45°)=(tanα+tan45°)÷(1-tanα×tan45°)=(1+tanα)÷(1-tanα)=(1-ta
tan(α+π/4)化简
tan(α+π/4)化简
tan(α+π/4)化简
tan(α+45°)
=(tanα+tan45°)÷(1-tanα×tan45°)
=(1+tanα)÷(1-tanα)
=(1-tanα)分之(1+tanα)
tan(α+π/4)化简
(tanπ/4+tanα)/(1-tanπ/4tanα)怎么解
化简cos2α/tan(π/4+α)
tan(π/4-α)化简,
化简tan(7π+α)
化简tan(x+π/4)+tan(x+π/4)
化简tan(x+π/4)-tan(x-π/4)
化简tan(π/4+a)-tan(π/4-a)]
tan(4/π+α)=3 求tanα?
化简:[tan(π/4+β)-tan(π/4-β)]/tan2β-tan(π/4+β)tan(π/4-β)
化简:[tan(π/4+a)-tan(π/4-a)]/tan2a-tan(π/4+a)tan(π/4-a)
化简:{[tan(π/4+a)-tan(π/4-a)]/tan2a} *tan(π/4+a)
化简:[tan(5/4)π+tan(5/12)π]/[1-tan(5/12)π]
化简:[tan(5π)/4+tan(5π)/12]/[1-tan(5π)/12]
已知tanα/2=2,求tanα与tan(α+π/4)
化简sin(9π+α)tan(3/2π+α)/cos(-4π-α)tan(15π+α)tan(7/2π-α)
化简:1+tanα/1-tanα
化简1+tanαtanα/2