(-4x^4y+7/2x^2y-2xy)/(-2/1xy)+(-2x)^3
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(-4x^4y+7/2x^2y-2xy)/(-2/1xy)+(-2x)^3(-4x^4y+7/2x^2y-2xy)/(-2/1xy)+(-2x)^3(-4x^4y+7/2x^2y-2xy)/(-2/1
(-4x^4y+7/2x^2y-2xy)/(-2/1xy)+(-2x)^3
(-4x^4y+7/2x^2y-2xy)/(-2/1xy)+(-2x)^3
(-4x^4y+7/2x^2y-2xy)/(-2/1xy)+(-2x)^3
-2/1是-2分之1?
2分之1是1/2,
/是除号
(-4x^4y+2/7x^2y-2xy)/(-1/2xy)+(-2x)^3
=8x^3-(4/7)x+4-8x^3
=4-(4/7)x
[-4x^4y+(7/2)x^2y-2xy]/(-2xy)+(-2x)^3
=2x^3-(7/4)x+1-8x^3
=-6x^3-(7/4)x+1.
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(x^-4y^)/(x^+2xy+y^)/(x+2y)/(2x^+2xy)
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求(3x^+y^-5xy)-【2x^-(-4xy-y^+7x^)】=?
(x^2+2xy+y^2-4xy)*(x^2-2xy+y^2+4xy)
已知x*x-4xy+4y*y=0 求[2x(x+y)-y(x+y)]/(4x*x-4xy+y*y)的值?
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化简2(x²y+xy)-3(x²y-xy)-4x²y
已知1/x-1/y=2,求3x+7xy-3y/2x-3xy-2y答案是1/x-1/y=2(y-x)/xy=2 得:x-y=-2xy(3x+7xy-3y)/(2x-3xy-2y)=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy)=xy/(-7xy)=-1/7 谁能帮我解释一下=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy) 是怎