批处理 %date:0,4%%date:5,2%%date:8,2%_%time:0,2%%time:3,2% 输出是 20120823_ 926 小时想变09怎办
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批处理%date:0,4%%date:5,2%%date:8,2%_%time:0,2%%time:3,2%输出是20120823_926小时想变09怎办批处理%date:0,4%%date:5,2%
批处理 %date:0,4%%date:5,2%%date:8,2%_%time:0,2%%time:3,2% 输出是 20120823_ 926 小时想变09怎办
批处理 %date:0,4%%date:5,2%%date:8,2%_%time:0,2%%time:3,2% 输出是 20120823_ 926 小时想变09怎办
批处理 %date:0,4%%date:5,2%%date:8,2%_%time:0,2%%time:3,2% 输出是 20120823_ 926 小时想变09怎办
set t=%date:~0,4%%date:~5,2%%date:~8,2%_%time:~0,2%%time:~3,2%
echo %t: =%
%date:0,4%-%date:5,2%-%date:8,2%$%time:0,2%-%time:3,2%-%time:6,2%为什么批处理$后面老是报错
批处理 %date:0,4%%date:5,2%%date:8,2%_%time:0,2%%time:3,2% 输出是 20120823_ 926 小时想变09怎办
date
DATE
DATE
批处理里的 set last_date=%date:0,20% 能不能用别的语句替换 但是用途不变?
批处理定义新人求问,此处我定义一个时间如set d1=%date:0,4% 2013set d2=%date:5,2% 10set d3=%date:8,2% 30请问如何让他显示出20131030呢中间没有间隔,如果我用echo %d1%%d2%%d3% 2013 10 30是这样的格式此外,我如
var date=new Date(year,month,0);
date of
Expiration date
value date
“issue date
date on
Date是什么意思
exp date
exp.date
PO Date
date是什么意思?