(3/8x-15)/(5/8x-15)=7:5
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(3/8x-15)/(5/8x-15)=7:5(3/8x-15)/(5/8x-15)=7:5(3/8x-15)/(5/8x-15)=7:5内项积等于外项积所以7(5/8x-15)=5(3/8x-15)
(3/8x-15)/(5/8x-15)=7:5
(3/8x-15)/(5/8x-15)=7:5
(3/8x-15)/(5/8x-15)=7:5
内项积等于外项积
所以7(5/8x-15)=5(3/8x-15)
35/8x-105=15/8x-75
35/8x-15/8x=105-75
20/8x=30
x=30÷20/8
x=12
102*54-3780÷36
=5508-105
=5403
(39+39/61)÷39
=39÷39+39/61÷39
=1+1/61
=1又61分之1
(48-36*2/3)÷(1/4-1/5)
=(48-24)÷(1/20)
=24×20
=480
99*10.1
=99*101÷10
=(100-1)*(100+1)÷10
=(100²-1)÷10
=9999÷10
=999.9
证明(x+1)(X+3)(x+5)(x+7)+15=(X+8x)+22(x+8x)+120
x(x*x-6x-9)-x(x*x-8x-15)+2x(3-x)
1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550必须用解方程
通分:x+4/x^2-8x+15,x-5/x^2+x-12,x-3/x^2-x-20
X(x平方-6x-9)-x(x平方-8x-15)+2x(3-x)其中x=-六分之一
[(x+2)/(x+3)-(x+1)/(x+2)+(x+4)/(x+5)-(x+3)/(x+4)]/[(x的平方+7x+13)/(x的平方+8x+15)]
计算:[(x+2)/(x+3) - (x+1)/(x+2) + (x+4)/(x+5) - (x+3)/(x+4) / (x^2 + 7x + 13)/(x^2 + 8x + 15)
matlab解决约束非线性规划问题myfun.mfunction f=myfun(x)f=x(1)*x(13)+x(2)*x(14)+x(3)*x(15)+x(25)+1.697*(x(4)*x(16)+...x(5)*x(17)+x(6)*x(18)+x(26))+0.575*(x(7)*x(19)+x(8)*x(20)...+x(9)*x(21)+x(27))+0.723*(x(10)*x(22)+x(11)*x(23)+x(12)*x(24));
matlab解决约束非线性规划问题myfun.mfunction f=myfun(x)f=x(1)*x(13)+x(2)*x(14)+x(3)*x(15)+x(25)+1.697*(x(4)*x(16)+...x(5)*x(17)+x(6)*x(18)+x(26))+0.575*(x(7)*x(19)+x(8)*x(20)...+x(9)*x(21)+x(27))+0.723*(x(10)*x(22)+x(11)*x(23)+x(12)*x(24));
4x的平方+15x-5=0,求(-15x*x-18x+9)-(-3*x*x+19x-31)-8x
[(1+x)^20+(1+x)^19+(1+x)^18+(1+x)^17+(1+x)^16+(1+x)^15+(1+x)^14+(1+x)^13+(1+x)^12+(1+x)^11+(1+x)^10+(1+x)^ 9+(1+x)^8+(1+x)^7+(1+x)^6+(1+x)^5+(1+x)^4+(1+x)^3+(1+x)^2+(1+x)]=28.51
15-(8-5x)=7x+(4-3x)
15-(8-5x)=7x+(14-3x)
15X(4X-8)-5X(2X+10)=6X(5X-20)
x(-6x-9)-x(-8x-15)+2x(3-x)=?
8(x+15)-20=10x 2(100-x)-15=150-x 25x-165=10(15-x) 5(x-10)=3x-6
8(x+15)-20=10x 2(100-x)-15=150-x 25x-165=10(15-x) 5(x-10)=3x-6
证明(x+1)(x+3)(x+5)(x+7)+15=(x^2+8x)^2+22(x^2+8x)+120