[(-1)^3÷2/9+2^2001×(-0.5)^2001-3^3×(-3/2)^2]÷│-4÷2×(-1/2)^2│
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[(-1)^3÷2/9+2^2001×(-0.5)^2001-3^3×(-3/2)^2]÷│-4÷2×(-1/2)^2│[(-1)^3÷2/9+2^2001×(-0.5)^2001-3^3×(-3/2
[(-1)^3÷2/9+2^2001×(-0.5)^2001-3^3×(-3/2)^2]÷│-4÷2×(-1/2)^2│
[(-1)^3÷2/9+2^2001×(-0.5)^2001-3^3×(-3/2)^2]÷│-4÷2×(-1/2)^2│
[(-1)^3÷2/9+2^2001×(-0.5)^2001-3^3×(-3/2)^2]÷│-4÷2×(-1/2)^2│
原式=-1÷2/9+2x(-0.5)^2001-9x4/9÷1/8
=9/2+(-1)-162
=158.5
[(-1)^3÷2/9+2^2001×(-0.5)^2001-3^3×(-3/2)^2]÷│-4÷2×(-1/2)^2│
计算1001-1/2001-2/2001-3/2001-...-2001/2001
2001/1+2002/2+2001/3+2001/4+.+2001/2001
1/2001+2/2001+3/2001...+4000/2001+4001/2001
用递等式计算两道题(1)1×2÷3×4÷5×6÷7×8÷9×10÷11×12(2)(1+3+5...+2001+2003+2005)-(2+4+6...+2000+2002+2004)
1÷(1÷2)÷(2÷3)÷(3÷4)÷.÷(8÷9)÷(9÷10)=?
11/15×7/9+2/9×11/15-11/15÷9/4 简算!1/2000×2001 +1/2001乘以2002 + 1/2002×2003 + 1/2003
1/2001+2/2001+3/2001+4/2001+``````````+1999/2001+2001/2001用简便算法写过程
1又1/2001+2又2/2001+3又3/2001+4又4/2001+.+2000又2000/2001
在下列数字之间添上适当的运算符号(+、-、×、÷或()),使等式成立.9 8 7 6 5 4 3 2 1=2001
2002*2001-2001*2000+2000*1999-.-3*2+2*1
(-1)+(+2)+(-3)+(+4)+.(-2001)+(+2002)+(-2003)+(+2004) 符号:+ ﹣ × ÷
【-1/3X[-1/2]+[-1/9]÷2/3】÷(-1/2)³
-1^2×(-3)^2009×(-2)^2008÷9/2
2002的2次方÷1999×2001-3
(1*1+2*2)/(1*2)+(2*2+3*3)/(2*3)+……+(2000*2000+2001*2001)/(2000*2001)
1*1+2*2/1*2+2*2+3*3/2*3+...+2001*2001+2002*2002/2001*2002
1÷1×3 1÷2×4 ...1÷9×11等于多少