100+99.9-99.8-99.7+99.6+99.5-99.4-99.3+…...+0.4+0.3-0.2-0.1
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100+99.9-99.8-99.7+99.6+99.5-99.4-99.3+…...+0.4+0.3-0.2-0.1100+99.9-99.8-99.7+99.6+99.5-99.4-99.3+….
100+99.9-99.8-99.7+99.6+99.5-99.4-99.3+…...+0.4+0.3-0.2-0.1
100+99.9-99.8-99.7+99.6+99.5-99.4-99.3+…...+0.4+0.3-0.2-0.1
100+99.9-99.8-99.7+99.6+99.5-99.4-99.3+…...+0.4+0.3-0.2-0.1
(100-99.8)+(99.9-99.7)+(99.6-99.4)+.+(0.3-0.1)
=0.2*250
=50
98
从99.9到-0.1一共有1000项
注意每四项的和加起来都为0
所以:100+99.9-99.8-99.7+99.6+99.5-99.4-99.3+…...+0.4-0.3-0.2+0.1=100
但是:你所给的题目有错误,+0.3是否为-0.3,-0.1为+0.1,否则没有办法找到规律进行计算
100+99.9-99.8-99.7+99.6+99.5-99.4-99.3+…...+0.4+0.3-0.2-0.1
=100+0.1-0.1+0.1-0.1+………+0.1-0.1
=100
99.9+99.8-99.7=?简便计算
简算100+99.9-99.8-99.7+···+0.4+0.3-0.2-0.1
100+99.9-99.8-99.7+99.6+99.5-99.4-99.3+…...+0.4+0.3-0.2-0.1
小学数学,递等式100+99.9-99.8-99.7+99.6+99.5-99.4-99.3+……+0.4+0.3-0.2-0.1=
19.94+99.7×99.8
matlab里的问题,>> n=2:40;>> a(n)=[102.0 101.9 102.0 102.6 100.9 100.0 100.3 100.0 100.1 100.0 100.0 100.2 100.0 99.9 99.8 99.8 99.9 100.0 99.9 99.7 99.8 99.8 99.9 99.9 99.9 99.9 99.6 99.9 100.0 100.3 100.3 100.1 100.1 100.2 100.6 100.8 101.6 102.
巧算 99.6+99.8+99.7+99.1
19.94+99.7×99.8 help me
111.(100个1)*99.9(100个9)等于几?
99.9【100个9】×99.【100个9】+99.【100个9】+100.0【100个0】简便运算
111.(100个1)*99.9(100个9)的积里有( )个位数的数是偶数
太阳的质量占整个太阳系() 1、99% 2、99.9% 3、99.8% 4、99.98%
99.9/100/0.1等于多少
99.9^2+19.98+1/100
1.1+1.91+1.991+.+1.{99.9}1 { }处为100个9
99.9*99.9+199.999.9都表示有99个9
99.9乘99.9 99.9乘(100减0.1)这样做对吗
矩阵次方问题,求助帮我计算两个矩阵的100,1000,10000次方的结果矩阵1:[99.6% 0.4% 0.0% 0.0% 99.6% 0.4% 0.0% 0.2% 99.8%]矩阵2:[ 99.9% 0.1% 0.0% 0.3% 99.4% 0.3% 0.2% 0.2% 99.6%]分别求下这两个矩阵的100,1000,10000次方